Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.5 Inequalities - R.5 Exercises - Page R-21: 38

Answer

$p^2-16p\gt0$ $p(p-16)\gt0$ $p\lt0$ and $16\lt p$
1530560196

Work Step by Step

Step 1: Factorize inequality (common factor) Step 2: The inequality function will be greater than $0$ for $p\lt0$ and $16\lt p$
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