Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.5 Inequalities - R.5 Exercises - Page R-21: 36

Answer

$3a^2+a\gt10$ $3a^2+a-10\gt0$ $(3a-5)(a+2)\gt0$ $a\gt\frac{5}{3}$ and $a\lt-2$
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Work Step by Step

Step 1: Subtract 10 from both sides of the inequality Step 2: Factorize quadratic inequality (trinomial) Step 3: The inequality function is greater than $0$ for $a\gt\frac{5}{3}$ and $a\lt-2$
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