Answer
$p \geq \frac{-17}{7}$
Work Step by Step
$\frac{3}{5}(2p+3) \geq \frac{1}{10}(5p+1)$
1. Distribute $\frac{3}{5}$ and $\frac{1}{10}$
$\frac{6}{5}p+\frac{9}{5} \geq \frac{1}{2}p+ \frac{1}{10}$
2. Multiply both sides of the inequality:
$12p+18 \geq 5p+1$
3. Move the variable to the left side (and change its sign) and the constant to the right (also changing its sign):
$12p-5p \geq 1-18$
4. Combine like terms:
$7p \geq -17$
5. Divide both sides by 7 to get the variable alone and to get your answer:
$p \geq \frac{-17}{7}$
