## Calculus with Applications (10th Edition)

Published by Pearson

# Chapter R - Algebra Reference - R.5 Inequalities - R.5 Exercises - Page R-21: 25

#### Answer

$p \geq \frac{-17}{7}$

#### Work Step by Step

$\frac{3}{5}(2p+3) \geq \frac{1}{10}(5p+1)$ 1. Distribute $\frac{3}{5}$ and $\frac{1}{10}$ $\frac{6}{5}p+\frac{9}{5} \geq \frac{1}{2}p+ \frac{1}{10}$ 2. Multiply both sides of the inequality: $12p+18 \geq 5p+1$ 3. Move the variable to the left side (and change its sign) and the constant to the right (also changing its sign): $12p-5p \geq 1-18$ 4. Combine like terms: $7p \geq -17$ 5. Divide both sides by 7 to get the variable alone and to get your answer: $p \geq \frac{-17}{7}$

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