Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.3 Rational Expressions - R.3 Exercises - Page R-11: 31


$\dfrac{8}{3(a-1)}+\dfrac{2}{a-1}=\dfrac{14}{3(a-1)}$ or $\dfrac{8}{3(a-1)}+\dfrac{2}{a-1}=\dfrac{14}{3a-3}$

Work Step by Step

$\dfrac{8}{3(a-1)}+\dfrac{2}{a-1}$ Evaluate the sum of these two fractions by using the LCD, which is $3(a-1)$ in this case: $\dfrac{8}{3(a-1)}+\dfrac{2}{a-1}=\dfrac{8+(2)(3)}{3(a-1)}=...$ Simplify: $...=\dfrac{8+6}{3(a-1)}=\dfrac{14}{3(a-1)}$
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