Answer
$\dfrac{8}{3(a-1)}+\dfrac{2}{a-1}=\dfrac{14}{3(a-1)}$
or
$\dfrac{8}{3(a-1)}+\dfrac{2}{a-1}=\dfrac{14}{3a-3}$
Work Step by Step
$\dfrac{8}{3(a-1)}+\dfrac{2}{a-1}$
Evaluate the sum of these two fractions by using the LCD, which is $3(a-1)$ in this case:
$\dfrac{8}{3(a-1)}+\dfrac{2}{a-1}=\dfrac{8+(2)(3)}{3(a-1)}=...$
Simplify:
$...=\dfrac{8+6}{3(a-1)}=\dfrac{14}{3(a-1)}$
