Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.3 Rational Expressions - R.3 Exercises - Page R-11: 18


$\displaystyle \frac{3}{10}$

Work Step by Step

$\displaystyle \frac{9y-18}{6y+12}\cdot \displaystyle \frac{3y+6}{15y-30}=$ ...factor out 9 in the first numerator, ... factor out 6 in the first denominator ... factor out 15 in the second denominator $= \displaystyle \frac{9(y-2)}{6(y+2)}\cdot\frac{3(y+2)}{15(y-2)}$ ... apply property: $\displaystyle \frac{P}{Q}\cdot\frac{R}{S}=\frac{PR}{QS}$ $... 9=3\cdot 3, 6=3\cdot 2, 15=3\cdot 5$ $= \displaystyle \frac{3\cdot 3\cdot 3(y-2)(y+2)}{3\cdot 2\cdot 3\cdot 5(y+2)(y-2)}\qquad$ ... reduce: 3, 3, $(y-2),\ (y+2)$ $=\displaystyle \frac{3}{10}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.