Calculus with Applications (10th Edition)

$\dfrac{3}{p}+\dfrac{1}{2}=\dfrac{p+6}{2p}$
$\dfrac{3}{p}+\dfrac{1}{2}$ Evaluate the sum of these two rational expressions with different denominators by using $2p$ as least common denominator: $\dfrac{3}{p}+\dfrac{1}{2}=\dfrac{6+p}{2p}=\dfrac{p+6}{2p}$