Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.3 Rational Expressions - R.3 Exercises - Page R-11: 30


$\dfrac{5}{2r+3}-\dfrac{2}{r}=\dfrac{r-6}{r(2r+3)}$ or $\dfrac{5}{2r+3}-\dfrac{2}{r}=\dfrac{r-6}{2r^{2}+3r}$

Work Step by Step

$\dfrac{5}{2r+3}-\dfrac{2}{r}$ Evaluate the subtraction of these two fractions by using the LCD, which is $r(2r+3)$ in this case: $\dfrac{5}{2r+3}-\dfrac{2}{r}=\dfrac{5r-2(2r+3)}{r(2r+3)}=...$ Simplify: $...=\dfrac{5r-4r-6}{r(2r+3)}=\dfrac{r-6}{r(2r+3)}$
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