## Calculus with Applications (10th Edition)

$2(3r^{2}+4r+2)-3(-r^{2}+4r-5)=9r^{2}-4r+19$
$2(3r^{2}+4r+2)-3(-r^{2}+4r-5)$ Multiply $2$ and $-3$ by each term inside their respective parentheses and then simplify by combining like terms: $(6r^{2}+8r+4)+(3r^{2}-12r+15)=9r^{2}-4r+19$