## Calculus with Applications (10th Edition)

$(3p+2)(5p^{2}+p-4)=15p^{3}+13p^{2}-10p-8$
$(3p+2)(5p^{2}+p-4)$ Evaluate the product indicated by multiplying the first term and second term of the first factor by every element in the second factor separately: $(3p+2)(5p^{2}+p-4)=...$ $...=15p^{3}+3p^{2}-12p+10p^{2}+2p-8=...$ Simplify: $...=15p^{3}+13p^{2}-10p-8$