# Chapter R - Algebra Reference - R.1 Polynomials - R.1 Exercises - Page R-5: 2

$(-4y^{2}-3y+8)-(2y^{2}-6y-2)=-6y^{2}+3y+10$

#### Work Step by Step

$(-4y^{2}-3y+8)-(2y^{2}-6y-2)$ To evaluate the subtraction, change the sign of every term inside the second parentheses and evaluate by combining like terms: $-4y^{2}-3y+8-2y^{2}+6y+2=-6y^{2}+3y+10$

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