Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.1 Polynomials - R.1 Exercises: 2

Answer

$(-4y^{2}-3y+8)-(2y^{2}-6y-2)=-6y^{2}+3y+10$

Work Step by Step

$(-4y^{2}-3y+8)-(2y^{2}-6y-2)$ To evaluate the subtraction, change the sign of every term inside the second parentheses and evaluate by combining like terms: $-4y^{2}-3y+8-2y^{2}+6y+2=-6y^{2}+3y+10$
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