## Calculus with Applications (10th Edition)

$(-4y^{2}-3y+8)-(2y^{2}-6y-2)=-6y^{2}+3y+10$
$(-4y^{2}-3y+8)-(2y^{2}-6y-2)$ To evaluate the subtraction, change the sign of every term inside the second parentheses and evaluate by combining like terms: $-4y^{2}-3y+8-2y^{2}+6y+2=-6y^{2}+3y+10$