Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.1 Polynomials - R.1 Exercises: 15

Answer

$(3p-1)(9p^{2}+3p+1)=27p^{3}-1$

Work Step by Step

$(3p-1)(9p^{2}+3p+1)$ Evaluate the product indicated by multiplying the first term and second term of the first factor by every element in the second factor separately: $(3p-1)(9p^{2}+3p+1)=...$ $...=27p^{3}+9p^{2}+3p-9p^{2}-3p-1=...$ Simplify: $...=27p^{3}-1$
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