Answer
$B(t)= 0.02016t^3- 0.646t^2 +15.86t +839700$
Work Step by Step
$B{'}(t)=0.06048t^2-1.292t+15.86$
Taking antiderivative
$B(t)=\frac{ 0.06048t^3 }{3}- \frac{ 1.292t^2 }{2}+15.86t +C$ ................... eq(1)
Putting $t=0$
$B(0)=C$
$B(0)=C=839700$
Putting in eq (1)
$B(t)= 0.02016t^3- 0.646t^2 +15.86t +839700$
