Answer
$a\ln x-bx+C$
Work Step by Step
$$\int \frac{g(x)}{x} dx$$
Substitute $g(x)=a-bx$:
$$\begin{align*}
\int \frac{g(x)}{x} dx&=\int \frac{a-bx}{x} dx\\
&=\int \left(\frac{a}{x}-b\right) dx\\
&=a\ln x-bx+C.
\end{align*}$$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 7 - Integration - 7.1 Antiderivatives - 7.1 Exercises - Page 367: 61
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