Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 4 - Calculating the Derivative - 4.3 The Chain Rule - 4.3 Exercises: 5

Answer

$f(g(k)=320k^2+224k+39$

Work Step by Step

In order to find $f(g(k))$ let's find $g(k)$ first: $g(k) = 8k+3$ Then subsitute in $f(x)$ $f(g(k))=5(8k+3)^2-2(8k+3)=320k^2+224k+39$
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