#### Answer

$s'(t) =(144t^3)(2t^4+5)^{1/2}$

#### Work Step by Step

In order to derivate this function you have to apply the chain rule
Let's make a «u» substitution to make it easier
$u = 2t^4+5 $
$f(u) =12u^{3/2} $
Derivate the function:
$s'(u) = 18u^{1/2}u'$
Now let's find u'
$u' = 8t^3$
Then undo the substitution, simplify and get the answer:
$s'(t) = 18(8t^3)(2t^4+5)^{1/2}$
$s'(t) =(144t^3)(2t^4+5)^{1/2}$