Answer
$\frac{6}{5}$
Work Step by Step
$\lim\limits_{x \to -3}\frac{x^{2}-9}{x^{2}+x -6} = \lim\limits_{x \to -3}\frac{(x-3)(x+3)}{(x+3)(x-2)}= \lim\limits_{x \to -3} \frac{x-3}{x-2} =\frac{6}{5}$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 3 - The Derivative - 3.1 Limits - 3.1 Exercises - Page 137: 34
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