Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.4 Exponential Functions - 2.4 Exercises - Page 86: 28

Answer

$$ e^{x^{2}+5 x+6} =1 $$ The solution of the given equation is $$ x =-3 \quad \text { or } \quad x=-2. $$

Work Step by Step

$$ e^{x^{2}+5 x+6} =1 $$ Since the bases must be the same, write 1 as $e^{0}$ giving $$ \begin{aligned} e^{x^{2}+5 x+6} &=1 \\ e^{x^{2}+5 x+6} &=e^{0} \\ x 2+5 x+6 &=0 \\(x+3)(x+2) &=0 \\ x+3 &=0 \quad \text { or } \quad x+2=0 \\ x &=-3 \quad \text { or } \quad x=-2 \end{aligned} $$ So, the solution of the given equation is $$ x =-3 \quad \text { or } \quad x=-2. $$
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