Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.4 Exponential Functions - 2.4 Exercises - Page 86: 23

Answer

$$ 5^{-|x|} =\frac{1}{25} $$ The solution of the given equation is $$ x =2 \text { or } x=-2 $$

Work Step by Step

$$ 5^{-|x|} =\frac{1}{25} $$ Since the bases must be the same, write $ \frac{1}{25} $ as $5^{-2 }$ and 64 as $ 2^{6} $ giving $$ \begin{aligned} 5^{-|x|} &=\frac{1}{25} \\ 5^{-|x|} &=5^{-2 } \\-|x| &=-2 \\ x &=2 \text { or } x=-2 \end{aligned} $$ So, the solution of the given equation is $$ x =2 \text { or } x=-2 $$
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