Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.4 Exponential Functions - 2.4 Exercises - Page 86: 20

Answer

$$ \left(e^{3}\right)^{-2 x} =e^{-x+5} $$ So, the solution of the given equation is $$ x=-1. $$

Work Step by Step

$$ \left(e^{3}\right)^{-2 x} =e^{-x+5} $$ Since the bases is the same, then we have $$ \begin{aligned}\left(e^{3}\right)^{-2 x} &=e^{-x+5} \\ e^{-6 x} &=e^{-x+5} \\-6 x &=-x+5 \\-5 x &=5 \\ x &=-1 \end{aligned} $$ So, the solution of the given equation is $$ x=-1. $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.