## Calculus with Applications (10th Edition)

The answer is C, because when x=1, $\frac{1}{3}^{(1-x)} = 1$ so $y=1$. And also when x=0, $\frac{1}{3}^{(1-x)} = \frac{1}{3}$ so $y=\frac{1}{3}$. The points (1,1) and (0,1/3) reflect the points shown in graph C.