Answer
$L_{1}=L_{0}-s\cot\theta $
Work Step by Step
The result of exercise $89$ is:
$\cot\theta=\dfrac{L_{0}-L_{1}}{s} $
$s\cot\theta=L_{0}-L_{1} $
$L_{1}=L_{0}-s\cot\theta $
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 13 - The Trigonometric Functions - Chapter Review - Review Exercises - Page 702: 90
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