Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 13 - The Trigonometric Functions - Chapter Review - Review Exercises - Page 702: 87

Answer

$\sin\theta=\frac{s}{L_{2}}$

Work Step by Step

In the right triangle $BDC$, with hypotenuse $CD=L_2$ and a leg $BC=s$, using the definition of sine it follows: $$\sin\theta=\dfrac{BC}{CD}=\dfrac{s}{L_{2}}$$
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