Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 13 - The Trigonometric Functions - 13.3 Integrals of Trigonometric Functions - 13.3 Exercises - Page 698: 32

Answer

$$1$$

Work Step by Step

$$\eqalign{ & \int_{ - \pi /2}^0 {\cos x} dx \cr & {\text{integrate by using the basic integration rule }}\int {\cos x} dx = \sin x + C\,\,\,\left( {{\text{page 692}}} \right) \cr & then \cr & = \left( {\sin x} \right)_{ - \pi /2}^0 \cr & {\text{use fundamental theorem of calculus }}\int_a^b {f\left( x \right)} dx = F\left( b \right) - F\left( a \right).\,\,\,\,\left( {{\text{see page 388}}} \right) \cr & = \sin \left( 0 \right) - \sin \left( { - \frac{\pi }{2}} \right) \cr & {\text{simplifying}} \cr & = 0 - \left( { - 1} \right) \cr & = 1 \cr} $$
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