Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 12 - Sequences and Series - 12.4 Infinite Series - 12.4 Exercises - Page 638: 21

Answer

$\frac{2}{9}$

Work Step by Step

The repeating decimal 0.2222222222 . . . can be expressed as the infinite geometric series: $0.222222..=0.2+0.2(\frac{1}{10})+0.2(\frac{1}{100})^{2}+0.2(\frac{1}{100})^{3}...$ $a=0.2$ $r=\frac{1}{10}$ $\Sigma=\frac{0.2}{1-\frac{1}{10}}=\frac{2}{9}$ and $\frac{2}{9}$ is also $0.22222222...$
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