Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 12 - Sequences and Series - 12.4 Infinite Series - 12.4 Exercises - Page 638: 17

Answer

$${S_1} = \frac{1}{7},{S_2} = \frac{{16}}{{63}},{S_3} = \frac{{239}}{{693}},{S_4} = \frac{{3800}}{{9009}},{S_5} = \frac{{22,003}}{{45,045}}$$

Work Step by Step

$$\eqalign{ & {a_n} = \frac{1}{{2n + 5}} \cr & {\text{Find the first five terms of the sequence}} \cr & {a_1} = \frac{1}{{2\left( 1 \right) + 5}} = \frac{1}{7} \cr & {a_2} = \frac{1}{{2\left( 2 \right) + 5}} = \frac{1}{9} \cr & {a_3} = \frac{1}{{2\left( 3 \right) + 5}} = \frac{1}{{11}} \cr & {a_4} = \frac{1}{{2\left( 4 \right) + 5}} = \frac{1}{{13}} \cr & {a_5} = \frac{1}{{2\left( 5 \right) + 5}} = \frac{1}{{15}} \cr & {\text{Then by definition of partial sum}} \cr & {S_1} = {a_1} = \frac{1}{7} \cr & {S_2} = {a_1} + {a_2} = \frac{1}{7} + \frac{1}{9} = \frac{{16}}{{63}} \cr & {S_3} = {a_1} + {a_2} + {a_3} = \frac{1}{7} + \frac{1}{9} + \frac{1}{{11}} = \frac{{239}}{{693}} \cr & {S_4} = {a_1} + {a_2} + {a_3} + {a_4} = \frac{1}{7} + \frac{1}{9} + \frac{1}{{11}} + \frac{1}{{13}} = \frac{{3800}}{{9009}} \cr & {S_5} = {a_1} + {a_2} + {a_3} + {a_4} + {a_5} = \frac{1}{7} + \frac{1}{9} + \frac{1}{{11}} + \frac{1}{{13}} + \frac{1}{{15}} = \frac{{22,003}}{{45,045}} \cr & {\text{the partial sums are}}: \cr & {S_1} = \frac{1}{7},{S_2} = \frac{{16}}{{63}},{S_3} = \frac{{239}}{{693}},{S_4} = \frac{{3800}}{{9009}},{S_5} = \frac{{22,003}}{{45,045}} \cr} $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.