## Calculus with Applications (10th Edition)

We are given $f(x)=\frac{1}{10}; [0;10]$ The expected value $\mu=5$ a. The median is $\int^{m}_{0}f(x)dx = \frac{1}{2}$ $\int^{m}_{0}\frac{1}{10} dx= \frac{1}{2}$ $\frac{1}{10}m - 0= \frac{1}{2}$ $m=5$ b. The probability between mean and median $P(5 \leq X \leq 5)=\int^{5}_{5}\frac{1}{10}dx =\frac{1}{10}x|^{5}_{5}=0$