Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 8 - Section 8.1 - Arc Length - 8.1 Exercises - Page 549: 36

Answer

$L=\infty$

Work Step by Step

$\frac{dy}{dx}=\frac{1}{\tan(x)}$ $L=\int_\frac{\pi}{2}^\pi\sqrt{1+\Big(\frac{1}{\tan(x)}\Big)^2}dx=\infty$
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