Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 8 - Section 8.1 - Arc Length - 8.1 Exercises - Page 549: 33

Answer

Total length of arc is 3

Work Step by Step

$y=(1-x^{\frac{2}{3}})^{\frac{3}{2}}$ $L=\int_a^b\sqrt{1+\Big(\frac{dy}{dx}\Big)^2}dx$ $a=0$; $b=1$ $\frac{dy}{dx}=-\frac{\sqrt{1-x^{\frac{2}{3}}}}{x^{\frac{1}{3}}}$ $L=\int_0^1\sqrt{1+\Big(-\frac{\sqrt{1-x^{\frac{2}{3}}}}{x^{\frac{1}{3}}}\Big)^2}dx=\frac{3}{2}$ Total length of arc is 3
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