Answer
$\frac{1}{3}\tan^3\theta$
Work Step by Step
Let $u=\tan\theta$. then $du=\sec^2\theta \ d\theta$. Now we can re-write the integral as
$$\int u^2 \ du = \frac{1}{3}u^3=\frac{1}{3}\tan ^3\theta$$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 5 - Section 5.5 - The Substitution Rule - 5.5 Exercises - Page 419: 50
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