Answer
$$\int\sinh^2 x\cosh xdx=\frac{\sinh^3 x}{3}+C$$
Work Step by Step
$$A=\int\sinh^2 x\cosh xdx$$
Let $u=\sinh x$
Then we have $du=\cosh xdx$.
Substitute into $A$: $$A=\int u^2du$$ $$A=\frac{u^3}{3}+C$$ $$A=\frac{\sinh^3 x}{3}+C$$
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