Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Section 5.5 - The Substitution Rule - 5.5 Exercises - Page 419: 13



Work Step by Step

$$A=\int\frac{dx}{5-3x}$$ Let $u=5-3x$ Then $du=-3dx$. So $dx=-\frac{1}{3}du$ Substitute into $A$, we have $$A=-\frac{1}{3}\int\frac{1}{u}du$$ $$A=-\frac{1}{3}\ln|u|+C$$ $$A=-\frac{1}{3}\ln|5-3x|+C$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.