Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Section 5.3 - The Fundamental Theorem of Calculus - 5.3 Exercises - Page 400: 56

Answer

The integral does not exist.

Work Step by Step

$\int_{-1}^{2} \frac{4}{x^3}~dx$ The graph of $~~\frac{4}{x^3}~~$ has a vertical asymptote at the point $x=0$. Therefore, the function is not continuous on the interval $[-1,2]$ and we can not apply the Fundamental Theorem to calculate the value of this integral. The integral does not exist.
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