Answer
$$y' = 4x^3cos^2(x^4)$$
Work Step by Step
$$y = \int\limits^{x^4}_0 {cos^2\theta} d\theta$$
Using FTC 1, substitute in the upper bound for $\theta$ and multiply the derivative of the upper bound(chain rule).
$$y'= cos^2(x^4) \times (x^4)'$$
Simplify.
$$y'= cos^2(x^4) \times 4x^3$$
$$y' = 4x^3cos^2(x^4)$$