Answer
$= \frac{4\pi}{3}$
Work Step by Step
$\int^{\sqrt 3}_{\frac{1}{\sqrt 3}} \frac{8}{1+x^{2}} dx$
$= 8\int^{\sqrt 3}_{\frac{1}{\sqrt 3}} \frac{1}{1+x^{2}} dx$
$= 8 \arctan x |^{\sqrt 3}_{\frac{1}{\sqrt 3}}$
$= 8[ (\arctan \sqrt 3) - (\arctan \frac{1}{\sqrt 3})]$
$= 8[ (\frac{\pi}{3}) - (\frac{\pi}{6})]$
$= 8[ (\frac{2\pi}{6}) - (\frac{\pi}{6})]$
$= 8(\frac{\pi}{6})$
$= (\frac{8\pi}{6})$
$= \frac{4\pi}{3}$