Answer
$\int_{\pi/6}^{2\pi} \cos x\, dx = -\frac{1}{2}$
Work Step by Step
$\int_{\pi/6}^{2\pi} \cos x\, dx$
$ = \sin x|^{2\pi}_{\pi/6}$
$ = \sin(2\pi) - \sin(\pi/6)$
$ = 0 - \frac{1}{2}$
$ = - \frac{1}{2}$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 5 - Section 5.3 - The Fundamental Theorem of Calculus - 5.3 Exercises - Page 400: 54
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