Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.9 - Antiderivatives - 4.9 Exercises - Page 355: 7


$-5x^{\frac{7}{5}}+40x^{\frac{1}{5}} +C$

Work Step by Step

Start with the function $\int (-7x^{2/5} + 8x^{-4/5})dx$. Use the power rule for antiderivatives to integrate each term: $-\frac{7x^{7/5}}{\frac{7}{5}}+\frac{8x^{1/5}}{\frac{1}{5}}+C$ Simplify the fractions to arrive at answer: $-5x^{\frac{7}{5}}+40x^{\frac{1}{5}} +C$
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