## Calculus: Early Transcendentals 8th Edition

$4x^{3}+4x^{2}+C$
$\int(x(12x+8))dx$ Distribute: $\int(12x^{2}+8x)dx$. Use power rule for antiderivatives on each of the two terms: $\frac{12}{3}x^{3}+\frac{8}{2}x^{2}+C$. Simplify fractions: $4x^{3}+4x^{2}+C$.