Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.9 - Antiderivatives - 4.9 Exercises - Page 355: 5

Answer

$4x^{3}+4x^{2}+C$

Work Step by Step

$\int(x(12x+8))dx$ Distribute: $\int(12x^{2}+8x)dx$. Use power rule for antiderivatives on each of the two terms: $\frac{12}{3}x^{3}+\frac{8}{2}x^{2}+C$. Simplify fractions: $4x^{3}+4x^{2}+C$.
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