Answer
$F(t)=3t-\ln|t|-\frac{6}{t}+C$, $t\ne 0$
Work Step by Step
$f(t)=\frac{3t^{4}-t^{3}+6t^{2}}{t^{4}}$
Dividing out, we get:
$f(t)=3-\frac{1}{t}+\frac{6}{t^{2}}$
These follow basic antiderivative rules.
$F(t)=3t-\ln|t|-\frac{6}{t}+C$, $t\ne 0$
