## Calculus: Early Transcendentals 8th Edition

$F(t)=3t-\ln|t|-\frac{6}{t}+C$, $t\ne 0$
$f(t)=\frac{3t^{4}-t^{3}+6t^{2}}{t^{4}}$ Dividing out, we get: $f(t)=3-\frac{1}{t}+\frac{6}{t^{2}}$ These follow basic antiderivative rules. $F(t)=3t-\ln|t|-\frac{6}{t}+C$, $t\ne 0$