## Calculus: Early Transcendentals 8th Edition

$F(x) = \frac{x}{5} - 2\ln|x| + C$, $x\ne0$
$f(x) = \frac{1}{5} - \frac{2}{x}$ Rewrite the second term as a product. $f(x) = \frac{1}{5} - 2(\frac{1}{x})$ Rewriting the second term makes it easy to take the antiderivative (since we already know the antiderivative of $\frac{1}{x}$). $F(x) = \frac{1}{5} - 2\ln|x|$ Now we take the antiderivative of the first term and add the constant. $F(x) = \frac{x}{5} - 2\ln|x| + C$, $x\ne 0$