Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.11 - Hyperbolic Functions - 3.11 Exercises: 33

Answer

$$h'(x)=2x\cosh{(x^2)} $$

Work Step by Step

$h'(x)=\frac{d}{dx}\sinh {(x^2)}$ Using the chain rule: $h'(x)=\frac{d\sinh {(x^2)}}{dx^2} \times \frac{dx^2}{dx}$ $=\cosh {(x^2)} \times 2x$ $=2x\cosh{(x^2)} $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.