Answer
$$h'(x)=2x\cosh{(x^2)} $$
Work Step by Step
$h'(x)=\frac{d}{dx}\sinh {(x^2)}$
Using the chain rule:
$h'(x)=\frac{d\sinh {(x^2)}}{dx^2}
\times \frac{dx^2}{dx}$
$=\cosh {(x^2)} \times 2x$
$=2x\cosh{(x^2)} $
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 3 - Section 3.11 - Hyperbolic Functions - 3.11 Exercises - Page 265: 33
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