Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.11 - Hyperbolic Functions - 3.11 Exercises - Page 265: 33


$$h'(x)=2x\cosh{(x^2)} $$

Work Step by Step

$h'(x)=\frac{d}{dx}\sinh {(x^2)}$ Using the chain rule: $h'(x)=\frac{d\sinh {(x^2)}}{dx^2} \times \frac{dx^2}{dx}$ $=\cosh {(x^2)} \times 2x$ $=2x\cosh{(x^2)} $
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