Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.11 - Hyperbolic Functions - 3.11 Exercises: 32

Answer

$$g'(x)=2\sinh x\cosh x$$

Work Step by Step

$g'(x)=\frac{d}{dx}\sinh^2 x$ Using the chain rule: $g'(x)=\frac{d\sinh^2 x}{d \sinh x} \times \frac{d\sinh x}{dx}$ $=2\sinh x \times \cosh x$ $=2\sinh x\cosh x$
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