Answer
$$f'(x)=e^x(\cosh x+\sinh x)$$
Work Step by Step
$f'(x)=\frac{d}{dx}e^x \cosh x$
Using the product rule:
$f'(x)=\cosh x\times\frac{d}{dx}e^x+e^x\times \frac{d}{dx}\cosh x$
$=e^x \cosh x+e^x\sinh x$
$=e^x(\cosh x+\sinh x)$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 3 - Section 3.11 - Hyperbolic Functions - 3.11 Exercises - Page 264: 30
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