Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 15 - Section 15.1 - Double Integrals over Rectangles - 15.1 Exercise - Page 1000: 19

Answer

18

Work Step by Step

Integrate with respect to dx first: $\int[xy-y^2sinx]dy$ with x limits from 0 to π/2 $=\int(π/2\times y+y^2)dy$ Integrate with respect to dy: $π/4\times y^2+1/3\times y^3$ with y limits from -3 to 3 $=9π/4+9-(9π/4-9)=18$
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