Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 15 - Section 15.1 - Double Integrals over Rectangles - 15.1 Exercise - Page 1000: 17

Answer

5/2-1/e

Work Step by Step

Integrate with respect to dx first: $\int[1/2\times x^2+xe^{-y}]dy$ with x limits from 1 to 2 $=\int[2+2e^{-y}-1/2-e^{-y}]dy$ $=\int(3/2+e^{-y})dy$ Integrate with respect to dy: $=3/2\times y-e^{-y}$ with y limits from 0 to 1 $=3/2-1/e-(0-1)=5/2-1/e$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.