Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.6 - Cylinders and Quadric Surfaces - 12.6 Exercises - Page 840: 34

Answer

Hyperboloid of two sheets

Work Step by Step

Rewrite as: $-x^2+y^2-4z^2=4 \implies \dfrac{-x^2}{4}+\dfrac{y}{4}-z^2=1$ On comparing the above form, we find that we have: Hyperboloid of two sheets $ \dfrac{-x^2}{a^2} -\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}=1$ We see that traces in planes y=k are ellipses parallel to the xy-plane and traces in x=k and y=k are parabolas parallel to the yz-plane.
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