Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.6 - Cylinders and Quadric Surfaces - 12.6 Exercises - Page 840: 32

Answer

Elliptic Paraboloid

Work Step by Step

Rewrite as: $y=4x^{2}+2z^{2} \implies \displaystyle \frac{y}{1}=\frac{x^{2}}{(1/2)^{2}}+\frac{z^{2}}{(\sqrt{2})^{2}}$ or, $\displaystyle \frac{y}{4}=\frac{x^{2}}{1}+\frac{z^{2}}{2}$ On comparing the above form we find that we have an Elliptic Paraboloid $\displaystyle \frac{z}{c}=\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}$ Thus we have: Traces in planes y=k are ellipses parallel to the xy-plane and traces in x=k and y=k are parabolas parallel to the yz-plane.
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