Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.6 - Cylinders and Quadric Surfaces - 12.6 Exercises - Page 840: 11

Answer

Elliptic Paraboloid

Work Step by Step

\[x=y^2+4z^2\] Evaluated at \(x=0\): \[ y^2+4z^2=0 \\ x=0 \quad y=0 \] evaluated at \(x=4\): \[ y^2+4z^2=4 \\ \frac{y^2}{4}+\frac{4z^2}{4} = 1 \\ \frac{y^2}{(2)^2}+\frac{z^2}{(1)^2} = 1 \\ \quad \text{Ellipse with radius 1 on z-axis and 2 on x-axis} \] Other way of solving is that it follows the standard formula of the Elliptic Paraboloid: \[\frac{z}{c}=\frac{x^2}{a^2}+\frac{y^2}{b^2}\] In this case the paraboloid is oriented along the \(x\)-axis (instead of the \(z\)-axis as in the standard form).
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