Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.6 - Cylinders and Quadric Surfaces - 12.6 Exercises: 21

Answer

$VII$

Work Step by Step

The equation $x^{2}+4y^{2}+9z^{2}=1$ is an ellipsoid so, it can be either Figure $IV$ or Figure $VII$. If we write the given equation in the standard form of an ellipsoid centered at the origin, we will have $\frac{x^{2}}{1^{2}}+\frac{4y^{2}}{(1/2)^{2}}+\frac{z^{2}}{(1/3)^{2}}=1$ The numbers $1,1/2$ and $1/3$ are the number of units you go along either side of the $x-, y-$ and $z$-axes, respectively, from the origin, that is, the center of the ellipsoid, to get to the surface of the ellipsoid. In Figure $VII$, the ellipsoid is more elongated along the x-axis and 1 (the number under $x^{2})$ is greater than $1/2$ and $1/3$, so it must be Figure $VII$.
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