Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.5 - Equations of Lines and Planes - 12.5 Exercises - Page 832: 69

Answer

$\sqrt {\frac{61}{14}}$

Work Step by Step

Distance formula is given as: $d=\frac{|a \times b|}{|a|}$ Cross product: $a \times b=\lt 6,-3,4\gt$ $|a \times b|=\sqrt {6^2+(-3)^2+4^2}=\sqrt {61}$ $d=\frac{\sqrt {61}}{\sqrt {14}}$ or, $d=\sqrt {\frac{61}{14}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.