## Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning

# Chapter 12 - Section 12.5 - Equations of Lines and Planes - 12.5 Exercises - Page 832: 35

#### Answer

$8x+y-2z=31$

#### Work Step by Step

The general form of the equation of the plane passing through the point $(a,b,c)$ and having normal vector $\lt l,m,n\gt$ is: $l(x-a)+m(y-b)+n(z-c)=0$ Thus the equation of the plane is: $-16(x-3)-2(y-5)+4(z+1)=0$ After simplification, we get $-16x-2y+4z+62=0$ Or, $8x+y-2z=31$

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